Easy Solver Usage
The Easy Solver is a heuristic solver for QUBO/HUBO expressions.
Solving a problem with the Easy Solver consists of the following two steps:
- Create an
EasySolverobject. - Call the
search()method with a parameter dict, which returns aSolobject.
Creating Easy Solver object
To use the Easy Solver, an EasySolver object is constructed with an expression as follows:
EasySolver(f)
Here, f is the expression to be solved. It must be simplified as a binary expression in advance by calling simplify_as_binary().
Search Parameters
Parameters are passed as a dict to the search() method.
| Parameter | Description | Default |
|---|---|---|
"time_limit" | Time limit in seconds (float). Set to 0 for no time limit. | 10.0 |
"target_energy" | Target energy (int). The solver terminates when a solution with energy ≤ this value is found. | (none) |
"topk_sols" | Number of top-k solutions to keep (int). | (disabled) |
"best_energy_sols" | Keep solutions with the best energy (int). 0 for unlimited. | (disabled) |
"enable_default_callback" | Print newly obtained best solutions (int, 1 to enable). | (disabled) |
Unknown parameter keys will cause a runtime error.
Searching Solutions
The Easy Solver searches for solutions by calling search(params), where params is a dict of search parameters. It returns a Sol object.
Multiple Solutions
When "topk_sols" is set in the parameter dict, the solver collects up to n solutions with the best energies encountered during the search. These can be retrieved by calling sol.sols() on the returned Sol, which returns a list of Sol objects sorted in increasing order of energy.
solver = qbpp.EasySolver(f)
sol = solver.search({"topk_sols": 5})
for s in sol.sols():
print(f"energy = {s.energy}")
Program Example
The following program searches for a solution to the Low Autocorrelation Binary Sequences (LABS) problem using the Easy Solver:
import pyqbpp as qbpp
size = 100
x = qbpp.var("x", size)
f = qbpp.expr()
for d in range(1, size):
temp = qbpp.expr()
for i in range(size - d):
temp += (2 * x[i] - 1) * (2 * x[i + d] - 1)
f += qbpp.sqr(temp)
f.simplify_as_binary()
solver = qbpp.EasySolver(f)
sol = solver.search({"time_limit": 5.0, "target_energy": 900, "enable_default_callback": 1})
bits = "".join("-" if sol(x[i]) == 0 else "+" for i in range(size))
print(f"{sol.energy}: {bits}")
In this example, the following options are set:
- a 5.0-second time limit,
- a target energy of 900, and
- a default callback that prints the energy and TTS whenever a new best solution is found.
Therefore, the solver terminates either when the elapsed time reaches 5.0 seconds or when a solution with energy 900 or less is found.
For example, this program produces the following output:
TTS = 0.000s Energy = 300162
TTS = 0.000s Energy = 273350
...
TTS = 2.691s Energy = 898
898: ++-++-----+--+--++++++---++-+-+--++-------++-++-+-+-+-+-++-++++-++-+++++-+-+--++++++---+++--+++---++